CHICAGO ( Associated Press) — The Chicago Cubs on Saturday agreed to a $177 million, seven-year deal with Dansby Swanson, adding a star shortstop to their rebuilding project.
The deal includes an absolute no-trade clause, according to a person with knowledge of the talks who spoke to The Associated Press on condition of anonymity, pending a physical.
Swanson was part of an all-star group of shortstops who became free agents, including Trey Turner, Carlos Correa and Xander Bogarts. He was the last of the four to choose the team.
Swanson was the first pick in the 2015 Amateur Draft out of Arizona, but was sent to Atlanta in a multimillionaire trade in December.
With the Braves, Swanson became part of a young base that brought the team back to the top of the NL East. He had a .248 batting average with 27 home runs and 88 RBI in 2021, helping Atlanta win its first World Series championship since 1995.
Swanson, 28, is coming off what could be his best major league season, batting .277 with 25 home runs and a career-high 96 RBI in 162 games. The shortstop was selected to the All-Star Game for the first time and took home the Gold Glove.
While Atlanta was able to sign some of its young stars to long-term, team-friendly deals, it could not do the same with Swanson. After the team was eliminated by Philadelphia in the Division Series, the Braves presented Swanson with a qualifying offer of $19.65 million, but the Kennesaw, Georgia native declined.
Swanson, who played in college at Vanderbilt, made his major league debut in 2016 with Atlanta. He hit .255 with 102 home runs and 411 RBI in 827 games.